已知ab=1,a+b=—3,求a的3次方+8b?

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已知ab=1,a+b=—3,求a的3次方+8b?
已知ab=1,a+b=—3,求a的3次方+8b?

已知ab=1,a+b=—3,求a的3次方+8b?
(a+b)^2 = a^2 + 2ab + b^2 = 9;a^2 + b^2 = 9 - 2ab = 7;
(a+b)^3 = a^3 + 3a^2 b + 3ab^2 + b^3 = a^3 + 3ab(a+b) + b^3 = a^3 -9 + b^3 = -27;
a^3 + b^3 = -18;
b ^ 3 = b b^2 = b (7 - a^2) = 7b - ab a = 7b - a = 7b -(-3 - b) = 8b + 3;
a^3 + 8b + 3 = -18; a^3 + 8b = -21