若x+y+z=2,x^2-(y+z)^2=8,则x-y-z=多少?
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若x+y+z=2,x^2-(y+z)^2=8,则x-y-z=多少?
若x+y+z=2,x^2-(y+z)^2=8,则x-y-z=多少?
若x+y+z=2,x^2-(y+z)^2=8,则x-y-z=多少?
x^2-(y+z)^2=(x+y+z)·(x-y-z)
∴ x-y-z=8÷2=4
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