limx→27((x-27)/(x^(1/3)-3))
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limx→27((x-27)/(x^(1/3)-3))
limx→27((x-27)/(x^(1/3)-3))
limx→27((x-27)/(x^(1/3)-3))
因为x-27=(x^(1/3)-3))[x^(2/3)+3x^(1/3)+9]
所以((x-27)/(x^(1/3)-3))=x^(2/3)+3x^(1/3)+9
所以,原极限=limx→27 [x^(2/3)+3x^(1/3)+9]=9+9+9=27
0?.......
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