40x+40（2x+11)=3200 怎么解?

解分式方程：1/X-2+1/X-6=1/X-7+1/X-11/X-2+1/X-6=1/X-7+1/X-11/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)1/(x-2)(x-1)=1/(x-7)(x-6)(x-2)(x-1)=(x-7)(x-6)x^2-3x+2=x^2-13x+4213x-3x=42-210x=40x=4 为什么要移向才能解 x+40=2x x=? 方程：40X+40(2X+11)=3200 40x+40（2x+11)=3200 怎么解? x-40%x= x{x+1}{x-1}}x-2}{x-3}-40 x^2-14x+40=0 x^2-8x+16=0 X^2-11=0 (35-X)*(40-2X)+40X+2X*(35-X)=35*40 11(6-x)/3(x-4)=10(5-x)/3(x-4)-5(6-x)/(x-2)(16x-13)/(4x-3)-(20x-24)/(4x-5)=(32x-30)/(8x-7)-(40x-43)/(8x-9)求x(包括增根) x(x+40)=3200如何解 20/(x-20)=(2x-40)/(x+40) x^3 - 13x^2 + 40x - 40 =0 已知x*x+x-1=0 求x*x*x-2x+11=? x-40%x-40%x=15 x(40-2x)=200 x=? 2x/40%=x+20x=? 2（15+2x）x+40x=246 X-40%X+1200=2/3X怎么算