有点急
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有点急
有点急
有点急
∵abc=1
∴ab+a+1=ab+a+abc=a(b+bc+1)
ca+c+1=ca+c+abc=c(a+ab+1)
∴原式
=(b+1)/(b+bc+1)+1/(a+ab+1)
=a(b+1)/a(b+bc+1)+1/(a+ab+1)
=a(b+1)/(ab+abc+a)+1/(a+ab+1)
=a(b+1)/(ab+a+1)+1/(a+ab+1)
=(ab+a+1)/(a+ab+1)
=1
不好意思?我最烦的就是方程┏ (^ω^)=☞。帮不了你哈~
a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)= a/(ab+a+abc)+b/(bc+b+abc)+c/(ac+c+abc)
=1/(bc+b+1)+1/(ac+c+1)+1/(ab+a+1)
=1
a/ab+a+1 + b/bc+b+1 + c/ca+c+1
=a/(ab+a+abc)+b/(bc+b+1)+c/(ca+c+abc)
=1/(b+1+bc)+b/(bc+b+1)+1/(a+1+ab)
=1/(bc+b+1)+b/(bc+b+1)+abc/(a+abc+ab)
=1/(bc+b+1)+b/(bc+b+1)+bc/(1+bc+b)
=(1+b+bc)/(bc+b+1)
=1.