求lim(x→0) (1-cos x) /x^2的极限
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 17:32:52
求lim(x→0) (1-cos x) /x^2的极限
求lim(x→0) (1-cos x) /x^2的极限
求lim(x→0) (1-cos x) /x^2的极限
x趋近于0的时候1-cos x等价于(1/2)x^2,这是书上的公式。
所以这个极限是1/2
求极限lim(x→0) cos(1/x)
求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限
求函数极限:lim(x->0) (cos x)^(1/x)
求函数极限lim x→0 e^x-x-1/x cos x
求极限:lim(x→0)ln(1+x²)/ (sec x- cos x)
lim(x→0)(1/x)*cos(1/x)
求极限lim(x→0)(1-根号cosx)/[x(1-cos根号x)]
求lim(x→0+) ( 2/π*cosπ/2(1-x))/x的极限
求lim(x→0) (1-cos x) /x^2的极限
求极限lim(1-√cosx)/(1-cos√x) (x→0+)
求极值lim(x→0)(sinx+x²cos(1/x))/xlim(x→0)(sinx+x²cos(1/x))/x/>
求lim (sec^2 x求极限lim (sec^2 x - 1 )/(1-cos x) X-0请写出过程,
求极限lim(x→0)(x^3sin1/x)/(1-cos^2x),要详细过程~
求 lim(x→∞)[sin(2/x)+cos(1/x)]^x的极限.
如何求 lim(n→∞)cos(x/2)cos(x/4)...cos(x/2n)
利用lim sinx/x =1或等价无穷小量求极限 lim (cosαx-cosβx)/x^2 x趋向0
求极限lim(x,y)→(0,0) [1-cos(x2+y2)]/[(x2+y2)e^x2y2]
lim(x→0) (1-cos(1-cosx))/(arctanx^2)^2求极限