(x+y)²-2x-2y+1 因式分解
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(x+y)²-2x-2y+1 因式分解
(x+y)²-2x-2y+1 因式分解
(x+y)²-2x-2y+1 因式分解
(x+y)²-2x-2y+1
=(x+y)²-2(x+y)+1
=(x+y-1)²
=(x+y)²-2x-2y+1,提取公因式
=(x+y)²-2(x+y)+1
令u=x+y,
=u²-2u+1,化成完全平方形式
=(u-1)²,再将x+y代入u
=[(x+y)-1]²
=(x+y-1)²
分组(x+y)^2+(x+y)
提取公因式(x+y)
得到原式=(x+y)(x+y+1)
计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy
x²-y²=1{(x-y)²-2(x-y-2)=7
因式分解:x²-y²+2y-1要有具体步骤
[(x-y)²+(x+y)(x-y)]除以2x
因式分解2x(x-y)^4 - x²(x-y)² + xy(y-x)²RT
1-x²+2xy-y²x²-y²+x-y麻烦用因式分解解
(x+y)²-2(x²-y²)+(y-x)²
分解公因式 (x+y)²-2(x²-y²)+(x-y)²
在线求助完全平方公式因式分解(1)-a²-1+2a(2)2x²y-x²-xy²(3)4x²-20x+25(4)(x²+1)²-4x²(5)(2x-y)²-2(2x-y)+1(6)(x+y)²-2(x²-y²)+(x-y)²
x²-4y² x+2y---------- ÷ --------分数线x²+2xy+y² x²+xyx²-4y² x+2y----------÷--------分数线x²+2xy+y² x²+xy(x+2y)(x-2y)x(x+y)=----------------(x+y)(x+y)(x+2y)(x-y)x=------(x+y)这样对了吗?
x²+|x+2y|+2x=-1 化简【{3x²+2y}{-2y+3x²}-{x²-2y}²+8y²】÷{-2x}²的值
2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y
若x²+xy-2y²=0,则x²+3xy+y²/x²+y²
x²+xy-2y²=0则x²+3xy+y²/x²+y²
(x-2y)²+2x-4y+1 因式分解
(x+y)²-2x-2y+1 因式分解
1、x²+4y²+_______=(x-2y)²
因式分解:(x-2y)²-(2x+y)²