25(x-1)²-9(2x+3)²=0 用因式分解
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25(x-1)²-9(2x+3)²=0 用因式分解
25(x-1)²-9(2x+3)²=0 用因式分解
25(x-1)²-9(2x+3)²=0 用因式分解
25(x-1)²-9(2x+3)²=0
[5(x-1)]²-[3(2x+3)]²=0
[5(x-1)+3(2x+3)][5(x-1)-3(2x+3)]=0
(11x+4)(-x-14)=0
11x+4=0 -x-14=0
x1=-4/11 x2=-14
(5(x-1))²-(3(2x+3))²=0
((5z-5)+(6x+9))((5x-5)-(6x+9))=0
∴11x-4=0或x+14=0
x1=4/11
x2=-14
[5(x-1)]²-[3(2x+3)]²=0
[5(x-1)-3(2x+3)][5(x-1)+3(2x+3)]=0
-(x+14)(11x+4)=0
x1=-14, x2=-4/11
25(x-1)²-9(2x+3)²=0 用因式分解
1.(ax+by)²+(bx-ay)²2.(x²-x)²-4(x²-x-1)3.4(x+y)²-9(x-y)²4.(a+b)(a-b)+4(b-1)5.x²+4xy+4y²-2x-4y-36.(x+1)(x+2)(x+3)(x+4)+17,3x²-11x+10
求几道因式分解1.(ax+by)²+(bx-ay)²2.(x²-x)²-4(x²-x-1)3.4(x+y)²-9(x-y)²4.(a+b)(a-b)+4(b-1)5.x²+4xy+4y²-2x-4y-36.(x+1)(x+2)(x+3)(x+4)+17,3x²-11x+10
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