我自己做出来了但是答案怎么都不对..The equilibrium reaction ZnO(g)+H2(g)===Zn(g)+H2O(g)At a temperature of 1180 ℃ and at a pressure of 4.8 atm has the following gaseous composition :Zn=35% H2=25% H2O=40% (by volume) calculate the gra
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/09 04:36:03
我自己做出来了但是答案怎么都不对..The equilibrium reaction ZnO(g)+H2(g)===Zn(g)+H2O(g)At a temperature of 1180 ℃ and at a pressure of 4.8 atm has the following gaseous composition :Zn=35% H2=25% H2O=40% (by volume) calculate the gra
我自己做出来了但是答案怎么都不对..
The equilibrium reaction
ZnO(g)+H2(g)===Zn(g)+H2O(g)
At a temperature of 1180 ℃ and at a pressure of 4.8 atm has the following gaseous composition :Zn=35% H2=25% H2O=40% (by volume) calculate the grams of zinc oxide present at equilibrium given 122.1 g of ZnO ,2 moles of H2 at 1180℃ and 1.5 atm
我自己做出来了但是答案怎么都不对..The equilibrium reaction ZnO(g)+H2(g)===Zn(g)+H2O(g)At a temperature of 1180 ℃ and at a pressure of 4.8 atm has the following gaseous composition :Zn=35% H2=25% H2O=40% (by volume) calculate the gra
这题没毛病?锌 氢气 水 的体积分数加起来都百分之百了,氧化锌是以气相存在的吗?