因式分解(x+y+z)3-x3-y3-z3
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因式分解(x+y+z)3-x3-y3-z3
因式分解(x+y+z)3-x3-y3-z3
因式分解(x+y+z)3-x3-y3-z3
(x+y+z)^3-x^3-y^3-z^3
=3yx^2+3xy^2+3xz^2+3yz^2+3zx^2+3zy^2+6xyz
=3xy(x+y)+3z^2(x+y)+3z(x^2+y^2+2xy)
=3xy(x+y)+3z^2(x+y)+3z(x+y)^2
=3(x+y)[xy+z^2+z(x+y)]
=3(x+y)[x(y+z)+z(y+z)]
=3(x+y)(x+z)(y+z)
(x+y+z)3-x3-y3-z3
=(x+y+z)3-(x+y+z)3
=0
(x+y+z)3-x3-y3-z3
=3x+3y+3z-3x-3y-3z
=(3x-3x)+(3y-3y)+(3z-3z)
=0
因式分解(x+y+z)3-x3-y3-z3
x3+y3+z3+(x+y)3+(y+z)3+(z+x)3因式分解
因式分解:x3(y-z)+y3(z-x)+z3(x-y)=
因式分解X2(Y+Z)+Y2(Z+X)+Z2(X+Y)-(X3+Y3+Z3)-2XYZ
x+y+z=0求 x3+y3+z3=?
X+Y+Z=0 X3+Y3+Z3=?3就是3次幂
(x加y加z)3次方--x3次方-y3次方-z3次方.
若x,y,z大于等于0,求证:x3+y3+z3大于等于3xyz
因式分解公式(x+y)3=(x-y)3=x3+y3=x3-y3=
x3+x-y-y3因式分解详细过程
先化简,再求值:(2x3-xyz)-2(x3-y3+xyz)+(xyz-2y3),其中x=1,y=2,z=-3
x3 y3 z3=x+y+z,x2+y2+z2=xyz的正实数解打错了,应该是x3+y3+z3=x+y+z
已只x+y+z=3,x2+y2+z2=3求x3+y3+z3的值
已知x+y+z=3,x2+y2+z2=19,x3+y3+z3=30则xyz=?
x+y+z=1,x2+y2+z2=2,x3+y3+z3=3,x4+y4+z4=?
分解因式:(x3+y3)2-(x3-y3)2因式分解 (x^3+y^3)^2-(x^3-y^3)^2
已知X+Y+Z=0,求X3次方+Y3次方+Z3次方等于多少?
已知x+y+z=2,x2+y2+z2=12则x3+y3+z3=