记cos(-180度)=k,tan100度等于多少

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记cos(-180度)=k,tan100度等于多少
记cos(-180度)=k,tan100度等于多少

记cos(-180度)=k,tan100度等于多少
cos(-80°)=cos80°=k,则sin80°>0且sin²80°=1-cos²80°=1-k²,则sin80°=√(1-k²),tan100°=-tan80°=-(sin80°)/(cos80°)=[-√(1-k²)]/k

tan(100°) = -5.6712818196177

即cos(80°)=k
即cos(100°)=-k
sin(100°)=根号(1-k^2)
故tan(100°)=根号(1-k^2)/(-k)

应该是cos(-80度)=k