y=[x-1],
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y=[x-1],
y=[x-1],
y=[x-1],
取整
应该不是中括号,而是绝对值吧
y'/y=1/x
y'-(1/x)y=xe^-x
y(x+y)+(x-y)²-(x+y)(x-y),其中x=-1/3,y=3
(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
x>=1,x-y
y=x-1(x
已知x+y=a,2x-y=-2a,求[(x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值
x.y都是自然数,且x(x-u)-y(y-x)+12,求x.y得值快1且x(x-y)-y(y-x)=12
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值.
y=[x-1],
设x,y满足约束条件x+y>=1,x-y>=-1,2x-y
设x,y满足约束条件x+y>=1,x-y>=-1,2x-y
{3(x+y)+3(y+x)=1,3(x+y)+4(y-x)=-1
常微分方程y'=(x+y)ln(x+y)-1
y'=(x-y+1)/(x+y-3)通解
2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51