f[X]=sin[X-π/4]+4根号2×sinXcosX—cos[X+π/4]—2 X∈[π/4,π/2]求函数最大值我算是2根号2—2,但答案是[17根号2—16]/8请大家算一下到底是哪个正确?我的过程=sin[X-π/4+π/2]+2根号2×sin2X—cos[X+π/4]—2=2根号

f(x)=根号2sin(2x+π/4)+2-根号2对称轴方程 f(x)=2sin^2(π/4+x)+根号3(sin^2x+cos^2x)f(x)=2sin^2(π/4+x)+根号3(sin^2x-cos^2x) 符号打错了 求f(x)=2sin(x+π/4)sin(x-π/4)+sin2X的最大值.（答案是根号2, 函数f(x)=sin(2x-π/4)-2根号2*sin^2(x)的最小正周期是多少 函数f(x)=sin(2x-π/4)-2根号2sin^2x的最小正周期 函数f(X)=sin(2x-π/4)-2根号2sin^2x的最小值 f(x)=sin(2x-π/4)-2根号2sin^2x的最小正周期为 函数f(x)=负根号3sin ^2x+sin x cos x f(a/2)=1/4-根号3/2求sin a值 f(x)=2sin(x/4)cos(x/4)-2根号3*sin²(x/4)+根号3 求1.当x∈[0,π],求f(x)值域2.f(x)单调递增区间 f(x)=2sinπ/4cosπ/4- 2根号3sin^2π/4+根号3 f(x)=2sinπ/4cosπ/4-2根号3sin^2π/4+根号3 已知函数f(x)=根号(sin(x/2)^4+4cos(x/2)^2)-根号(cos(x/2)^4+4sin(x/2)^2)(1)化简f(x),并求f(25π/6)(2)若0 已知f(x)=cos^4x-2根号3sinxcosx-sin^4x 化简 已知向量a=(根号2sin(4/π+x)+1,-根号3),b=(根号2sin(4/π+x)-1,cos2x函数f(x)=ab (1)若函数h(x)=f(x+t)已知向量a=(根号2sin(4/π+x)+1,-根号3),b=(根号2sin(4/π+x)-1,cos2x函数f(x)=ab(1)若函数h(x)=f(x+t)的图像关于(-6/π,0)对 已知函数f(x)=2根号3sin平方x-sin（2x-π/3) 已知函数f(x)=e^x*(cosx-sinx),求导f'(x)为什么我的做法不对:f(x)=e^x*(cosx-sinx)=e^x根号2(1/根号2*cosx-1/根号2*sinx) 就是配角公式==>f(x)=根号2*e^x*sin(π/4-x) 再求导f'(x)=根号2e^x*cos(π/4-x)+根号2*e^x*sin(π/4-x)再 f(x)=根号2sin(2x-π/4),x属于[π/8,3π/4],函数最大值? 化简f(x)=sin(x-π/4)+4*（根号2）sinxcosx-cos(x+π/4)-2