magnesium reacts with hydrochloric acid.Mg(s)+2HCl(aq)==MgCl2 (aq)+H2 (g)what volume of hydrogen at r.t.p.is produced if 6g of magnesium reacts with an excess of the acid?A 1 dm3B 6dm3C 12dm3D 24dm3说明原因和过程.

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magnesium reacts with hydrochloric acid.Mg(s)+2HCl(aq)==MgCl2 (aq)+H2 (g)what volume of hydrogen at r.t.p.is produced if 6g of magnesium reacts with an excess of the acid?A 1 dm3B 6dm3C 12dm3D 24dm3说明原因和过程.
magnesium reacts with hydrochloric acid.
Mg(s)+2HCl(aq)==MgCl2 (aq)+H2 (g)
what volume of hydrogen at r.t.p.is produced if 6g of magnesium reacts with an excess of the acid?
A 1 dm3
B 6dm3
C 12dm3
D 24dm3
说明原因和过程.

magnesium reacts with hydrochloric acid.Mg(s)+2HCl(aq)==MgCl2 (aq)+H2 (g)what volume of hydrogen at r.t.p.is produced if 6g of magnesium reacts with an excess of the acid?A 1 dm3B 6dm3C 12dm3D 24dm3说明原因和过程.
题目大意： 6g 镁与过量的盐酸反应生成多少体积的氢气
6g镁为0.25 mol
根据反应式1 mol镁生成1 mol氢气
0.25 mol镁就生成0.25 mol氢气
在标准状况下,1 mol任何气体所占的体积都约为22.4 L,0.25 mol氢气为5.6L
所以选B

问的是6克镁能生成多少表况下体积的氢气，动笔算算，实验出真知啊…

6g的Mg与过量的盐酸反应
6g的Mg 是1/4mol
从反应方程式看出 1/4mol的Mg可以产生1/4mol的氢气
按照1mol气体在标准状态下为22.4L来算 1/4mol就是6L左右 即6dm3

就是6克镁和足量盐酸反应，在常温常压下，生成的氢气体积。
生成了1/4摩尔氢气，体积应是5.6dm3
选B

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