已知x/2=y/3=z/0.5,求分式x+3y-z/2x-y+z的值

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已知x/2=y/3=z/0.5,求分式x+3y-z/2x-y+z的值
已知x/2=y/3=z/0.5,求分式x+3y-z/2x-y+z的值

已知x/2=y/3=z/0.5,求分式x+3y-z/2x-y+z的值
x/2=y/3=z/0.5
同乘1/2
x/4=y/6=z
所以x=4z,y=6z
所以
(x+3y-z)/(2x-y+z)
=(4z+3*6z-z)/(2*4z-6z+z)
=21z/3z
=7

x/2=y/3=z/0.5
可得:
x=2/3y
z=1/6y
x+3y-z/2x-y+z
即:
[(2/3y)+3y-(1/6y)]/[(4/3y)-y+(1/6y)]
=(7/2)/(1/2)
=7

7