2sin π/6 =sin π/3,吗,求解释,还有-sin π/6=sin- π/6吗
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2sin π/6 =sin π/3,吗,求解释,还有-sin π/6=sin- π/6吗
2sin π/6 =sin π/3,吗,求解释,还有-sin π/6=sin- π/6吗
2sin π/6 =sin π/3,吗,求解释,还有-sin π/6=sin- π/6吗
这两个问题都可以用公式来求sin(2α)=2sinαcosα sin(-α)=-sinα
第一个不是,第二个是
2sin π/6 =sin π/3,吗,求解释,还有-sin π/6=sin- π/6吗
化简sin(α+β)+sin(α-β)+2sinαsin(3π/2-β)=
sin^2(π/3-x)+sin^2(π/6+x)
2sin(α+π/3)=sinα+______
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sin0=0 sin(1/6π)=1/2sin(1/3π)=√3/2sin(1/2π)=1sin(2/3π)=√3/2sin(5/6π)=1/2sin(π)=0sin(-π)=0sin(-5/6π)=-1/2sin(-2/3π)=-√3/2sin(-1/2π)=-1sin(-1/3π)=-√3/2sin(-1/6π)=-1/2sin(7/6π)=-1/2sin(4/3π)=-√3/2sin(5/3π)=-√3/2sin(11/6π)=-1/
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