计算:(x-y)(-x-y)=1994*2006
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 20:39:53
计算:(x-y)(-x-y)=1994*2006
计算:(x-y)(-x-y)=
1994*2006
计算:(x-y)(-x-y)=1994*2006
(x-y)(-x-y)=(x-y)*[-(x+y)]=-[(x-y)*(x+y)]=-[x^2-y^2]=-x^2+y^2
1994*2006 =(2000-6)*(2000+6)=2000^2-6^2=4000000-36=3999964
-(x-2)
原式=-(x-2)(x+2)=-(x^2-4)。我希望这问题是经过你思考后确定不会做才问的。
(x-y)(-x-y)=y^2-x^2
1994×2006=(2000-6)×(2000+6)=4000000-36=3999964
计算:(x-y)(-x-y)=1994*2006
(x-2y)(x+y)+(x+y)计算
计算:(x-y)^2-(x+y)(x-y)
计算(-x-y)(y-x)+(-x-y)(x+y),
计算:y(x-y)^2+(y-x)^3=?
用行列式性质计算(需过程):(x,y,x+y; y,x+y,x; x+y,x,y )
计算:[(x+y)³ - (x+y)²]÷(x+y)²=_____
计算[(x+2y)²-(2x-y)²]÷(3x+y)=
计算:(x-y)²-(y+2x)(y-2x)=______.
计算:(x-2y)^2-2(x-2y)(x+2y)+(x+2y)^2=
计算-{-[-(3x-y)]}
计算 x²/(x+y) - (x-y)
计算 (x²/x+y)-x-y
行列式计算 x y x+y y x+y x x+y x y|x y x+y ||y x+y x ||x+y x y |
运用平方差计算..(-x+y)(-x-y)(-x+y)(x+y)
计算 :2(x-y)^2-(y-x)^2-(x+y)(y-x)
计算:[(x+y)³-2(x+y)²-4(x+y)]÷(x+y)
计算(x-y)^2×(x-y)^3×(y-x)×(y-x)^2