(x+x^2y)dx -(x^2y+y)dy =0的通解
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(x+x^2y)dx -(x^2y+y)dy =0的通解
(x+x^2y)dx -(x^2y+y)dy =0的通解
(x+x^2y)dx -(x^2y+y)dy =0的通解
y'、dy/dx称为导数或微商.y'是dy/dx的简略写法,对默认自变量求导数.比如y=f(t),y'就是dy/dt.
dy是微分,是差分的极限形式.dy=y'dx.
严格地说,dy/dx不是dy与dx的商,但许多运算性质与商类似.一般可以当作商来运算.
dy/dx=(2x*x*x*y-y*y*y*y)/(x*x*x*x-2x*y*y*y)
dy/dx=2y/x+3x/2y
x^y-y^x=2,求dy/dx
求dy/dx=(x-y+5)/(x+y-2)
(-2x-y+9)dy=(-y+x+3)dx
微分方程 dy/dx=(-2x)/y
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du(x,y)=2xycos(x^2y)dx+x^2cos(x^y)dy,求u(x,y)
dy/dx,y=(1+x+x^2)e^x
微积分.若x^y=y^x,则dy/dx.[x^2-xylnx]/[y^2-xylny]
(x+x^2y)dx -(x^2y+y)dy =0的通解
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