cos^2(π/6)
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cos^2(π/6)
cos^2(π/6)
cos^2(π/6)
cos(π/6)=√3/2
它的平方就是3/4
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cos^2(π/6)
利用诱导公式求三角函数值 cos 6/65π一,利用诱导公式:cos(2kπ+α)=cosα (k∈Z)和cos(π-α)=-cosα 得出cos65π/6=cos(65π/6-10π)=cos(5π/6)=cos(π-π/6)=-cosπ/6=-√3/2二,又或者cos65π/6=cos(11π-1π/6)=-cos(
cos(2x-π/3)+cos(2x+π/6)化简
若cos(π/4-a)cos(π/4+a)=(根号2 )/6,则cos2a
计算cos(a+5π/12)cos(a+π/6)+cos(π/12-a)cos(π/3-a)
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cos 2π/7 +cos 4π/7 +cos 6π/7=?
求cos(2π/7)*cos(4π/7)*cos(6π/7)的值
请问cos(2π/7)+cos(4π/7)+cos(6π/7)=?,
【紧急求助】计算:cosα+cos(2π/3 +α)+cos(4π/3 +α)
cos (2 a/7)+cos(4 a/7)+cos(6 a/7)=?
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)怎么解
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设角a=-35π/6,则2sin(π+α)cos(π-α)-cos(π+α)/ 1+sin^2α+sin(π-α)-cos^2(π+α)sina=sin(-35π/6)=sin(-6π+π/6)=1/2 cosα=根号3/22sin(π+α)cos(π-α)-cos(π+α)/ [1+sin^2α+sin(π-α)-cos^2(π+α)]=2(-sinα)(-cosα)+cosα/[1+sin²
求证:[tan(2π-α)cos(3π/2-α)cos(6π-α)]/[sin(α+3π/2)cos(α+3π/2)]=-tanα
cos(6+π/2)等于多少,怎么算啊
y=cos(2x+6/π)的周期
cos2A-cos2B=2cos(π/A)cos(π/6+A)知道的速度回答啊 cos2A-cos2B=2cos(π/6-A)cos(π/6+A)题目有误 不好意思