(sin91)^2+(sin92)^2+……+(sin180)^2=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/09 03:54:18
(sin91)^2+(sin92)^2+……+(sin180)^2=?
(sin91)^2+(sin92)^2+……+(sin180)^2=?
(sin91)^2+(sin92)^2+……+(sin180)^2=?
(sin91)^2+(sin92)^2+……+(sin180)^2
=(sin89)^2+(sin88)^2+……+(sin46)^2+(sin45)^2+(sin44)^2+……+(sin1)^2+(sin0)^2
=(sin89)^2+(sin88)^2+……+(sin46)^2+(sin45)^2+(cos46)^2+……+(cos89)^2
=[(sin89)^2+(cos89)^2]+……+[(sin46)^2+(cos46)^2]+(sin45)^2
=44*1+1/2
=89/2
sin(90+n)=cosn
sin(180-n)=sinn
cos=^2+sinn^2=1
原式===34+(根2)/2
(sin91)^2+(sin92)^2+……+(sin180)^2=?
sin91°<sin92°,cos91°<cos92°,tan91°<tan92°,cot91°<cot92°哪个是正确的?
Sin92=?三克油!
化简sin119 sin181 -sin91 sin29 等于
为什么sin91°等于cos91°?都在第几象限?
cos29°cos91°-sin91°sin29°=?RT
sin91度sin29度-cos91度cos29度
化简 sin119°sin181°-sin91°sin29°= 写个过程啊~
sinx+sinb+sin91度=0 ,cosx+cosb+cos91度=0,求cos(x-b)
已知sinα+sinβ+sin91=0,cosα+cosβ+cos91=0,则cos(α-β)=
已知sina+sinβ+sin91°=0,cosa+cosβ+cos91°=0则cos(a-β)=?
2
2
2
2
2
2
-2