1.a>0且a≠1 ①㏒a(1)+㏒a(a) ②㏒a(a²)-aˆ㏒a(3) 2.若6ˆa=8,求㏒6(4)

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1.a>0且a≠1 ①㏒a(1)+㏒a(a) ②㏒a(a²)-aˆ㏒a(3) 2.若6ˆa=8,求㏒6(4)
1.a>0且a≠1 ①㏒a(1)+㏒a(a) ②㏒a(a²)-aˆ㏒a(3) 2.若6ˆa=8,求㏒6(4)

1.a>0且a≠1 ①㏒a(1)+㏒a(a) ②㏒a(a²)-aˆ㏒a(3) 2.若6ˆa=8,求㏒6(4)
㏒a(1)+㏒a(a)=0+1=1
㏒a(a²)-aˆ㏒a(3) =2㏒a(a)-aˆ㏒a(3) =2-3=-1
6ˆa=8,则log6(8)=a
即a=log6(8)=log6(2^3)=3log6(2),即log6(2)=a/3
㏒6(4)=㏒6(2^2)=2㏒6(2)=2*a/3=2a/3

(1) 0+1 = 1
(2) 2-3 = -1
(3) log6(4) = log6 (6^a/2) = log6 (6^a) - log6 (2) = a - log6 (2)
而log6 (4) = log6 (2) + log 6(2)因此log6(2) = a/3, log6(4) = 2a/3