已知方程组{2x+y=6,x-3y=1,不解方程组,求7y(x-3y)²-(3y-x)²的值.已知方程组{2x+y=6,{x-3y=1.不解方程组,求7y(x-3y)²-(3y-x)²的值.已知方程组{2x+y=6,{x-3y=1.不解方程组,求7y(x-3y)²-(3y-x)³

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已知方程组{2x+y=6,x-3y=1,不解方程组,求7y(x-3y)²-(3y-x)²的值.已知方程组{2x+y=6,{x-3y=1.不解方程组,求7y(x-3y)²-(3y-x)²的值.已知方程组{2x+y=6,{x-3y=1.不解方程组,求7y(x-3y)²-(3y-x)³
已知方程组{2x+y=6,x-3y=1,不解方程组,求7y(x-3y)²-(3y-x)²的值.
已知方程组{2x+y=6,
{x-3y=1.不解方程组,求7y(x-3y)²-(3y-x)²的值.
已知方程组{2x+y=6,
{x-3y=1.不解方程组,求7y(x-3y)²-(3y-x)³的值。
打错了 ..不²是³..

已知方程组{2x+y=6,x-3y=1,不解方程组,求7y(x-3y)²-(3y-x)²的值.已知方程组{2x+y=6,{x-3y=1.不解方程组,求7y(x-3y)²-(3y-x)²的值.已知方程组{2x+y=6,{x-3y=1.不解方程组,求7y(x-3y)²-(3y-x)³
{2x+y=6 ①
{x-3y=1 ②
①减②得 x+4y=5
7y(x-3y)²-(3y-x)³=7y(x-3y)²+(x-3y)³
=7y(x-3y)²+(x-3y)(x-3y)²
=(7y+x-3y)(x-3y)²
=(x+4y)(x-3y)²
=5x1²
=5
=5

因为2X+Y=6,X-3Y=1,方程一减去方程二得X+4Y=5
所求原式=(X-3Y)² (7Y-3Y+X)=(X-3Y)²(X+4Y)=5

解方程组得y=4/7
原式=7y-(-1)=5