化简:(2-1)(2+1)(22+1)(24+1)…(216+1)+1=

来源：学生作业帮助网编辑：作业帮时间：2024/11/07 19:21:36

化简:(2-1)(2+1)(22+1)(24+1)…(216+1)+1=
化简:(2-1)(2+1)(22+1)(24+1)…(216+1)+1=

化简:(2-1)(2+1)(22+1)(24+1)…(216+1)+1=
原式=(2^2-1)(2^2+1)(2^4+1).(2^16+1)_+1
=(2^4-1)(2^4+1).(2^16+1)+1
=.
=(2^16-1)(2^16+1)-1
=2^32-1+1
=2^32

(2-1)(2+1) (22+1)(24+1)…(216+1)+1
=(22-1)(22+1)(24+1)…(216+1)+1
=(24-1)(24+1)…(216+1)+1
=232-1+1
=2的32次方

化简:(2-1)(2+1)(22+1)(24+1)…(216+1)+1= 化简 ||-X-1|-2| 1计算 2化简 1/3：1/2化简化简 1/立方根2+1 化简1/3:1/2 1-2^(-2008)/1-2^(-1)化简化简 (2n-1)*(2n+1) -1/2(-2)^n-1=化简化简(1/2x+1)(x-2) 化简 (2n+1)!／(2n-1)! 化简:根号(11...11—-22...22)有(2n个1)(n个2) 化简,4sin^2a(1-sin^2a)+cos^22a, 2√1/3化简化简:2(a+1)-a 根号2分之1化简化简：cos^2A-1 化简：|x-1|+|x+2|