如图,AB⊥BD于点D,AE交BD于点C,且BC=DC.求证:AB=ED
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如图,AB⊥BD于点D,AE交BD于点C,且BC=DC.求证:AB=ED
如图,AB⊥BD于点D,AE交BD于点C,且BC=DC.求证:AB=ED
如图,AB⊥BD于点D,AE交BD于点C,且BC=DC.求证:AB=ED
【应该是AB⊥BD于点B,DE⊥BD于点D】
证明:
∵AB⊥BD,DE⊥BD
∴∠ABC=∠EDC=90º
又∵∠ACB=∠ECD【对顶角相等】
BC=DC
∴⊿ABC≌⊿EDC(ASA)
∴AB=ED
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