若sin(π/6+a)=1/3,则cos(π/3—a)=_______,cos(2π/3+a)=________
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若sin(π/6+a)=1/3,则cos(π/3—a)=_______,cos(2π/3+a)=________
若sin(π/6+a)=1/3,则cos(π/3—a)=_______,cos(2π/3+a)=________
若sin(π/6+a)=1/3,则cos(π/3—a)=_______,cos(2π/3+a)=________
本题就是利用诱导公式
sin(π/6+a)=1/3
(1)cos(π/3—a)
= cos[(π/2)-(π/6+a)]
=sin(π/6+a)
=1/3
(2)cos(2π/3+a)
=cos[(π/2)+(π/6+a)]
=-sin(π/6+a)
=-1/3
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