[( log(x^2) + log(x^4) )/ log(100 x)] = 4 求X
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[( log(x^2) + log(x^4) )/ log(100 x)] = 4 求X
[( log(x^2) + log(x^4) )/ log(100 x)] = 4 求X
[( log(x^2) + log(x^4) )/ log(100 x)] = 4 求X
没有底数吗?
还是是lg
[( lg(x^2) + lg(x^4) )/ lg(100 x)]
=(2lgx+4logx)/lg(100x)
=6lgx/(2+lgx)=4
6lgx=8+4lgx
所以.lgx=4
x=10000
2log(m)y-log(m)x-log(m)z
log(x+5)=log(x)+log(2) log(8)+log(x)=log(24) 2log(x)=log(2x)+log(3)
log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4)
[( log(x^2) + log(x^4) )/ log(100 x)] = 4 求X
solve:log(x)+log(2x)=2
log(X+5)+log(X+2)=1
log₂X 怎样变为log₂(2X)
log底2(x-2)
log根号2(X-1)
x=log a 2
log(2)(x)log(2)(4x)-3log(2)(x)-12=0
简化2log (x + 4) – log(2x + 8) + log(x - 2)谢谢~
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