找规律题 若1/1X3+1/3X5+1/5X7+…+1/(2n-1)(2n+1)的值为17/35,求n的值.
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找规律题 若1/1X3+1/3X5+1/5X7+…+1/(2n-1)(2n+1)的值为17/35,求n的值.
找规律题 若1/1X3+1/3X5+1/5X7+…+1/(2n-1)(2n+1)的值为17/35,求n的值.
找规律题 若1/1X3+1/3X5+1/5X7+…+1/(2n-1)(2n+1)的值为17/35,求n的值.
1/(2n-1)(2n+1)=1/2×(1/2n-1 +1/2n+1)
原式=1/2×(1-1/3+1/3-1/5+……+1/2n-1 -1/2n+1)
=n/2n+1=17/35
所以n=17
左边=1/2(1-1/3+1/3-1/5+1/5-1/7+....+1/(2n-1)-1/(2n-1)+1/(2n+1
右边=17/35
即 n/(2n+1)=17/35
n=17
1/1x3 + 1/3x5 +....+1/(2n-1)(2n+1) = (1/1 - 1/3 +1/3 -1/5 +......+1/(2n-1) - 1/(2n+1)) /2= (1 - 1/(2n+1)) / 2= 17/35 ---> n = 17.
因式分解:x5+x3+1
找规律:1乘1,1乘2,2乘3,3乘5,接下去1x1 ,1x2 ,2x3 ,3x5 ,( ),( ).找规律
找规律题 若1/1X3+1/3X5+1/5X7+…+1/(2n-1)(2n+1)的值为17/35,求n的值.
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