2( x2 +1/x2) - 9( x + 1/x) + 14 =
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/08 17:12:30
2( x2 +1/x2) - 9( x + 1/x) + 14 =
2( x2 +1/x2) - 9( x + 1/x) + 14 =
2( x2 +1/x2) - 9( x + 1/x) + 14 =
令a=x+1/x
a²=x²+2+1/x²
2(a²-2)-9a+14=0
(2a-5)(a-2)=0
x+1/x=5/2
2x²-5x+2=0
(2x-1)(x-2)=0
x=1/2,x=2
x+1/x=2
(x-1)²=0
x=1
x=1/2,x=2,x=1
2(x²+1/x²+2)-9(x+1/x)+18=0
2(x+1/x)²-9(x+1/x)+18=0
设x+1/x=t
则有:2t²-9t+18=0
然后解x+1/x=t
2( x2 +1/x2) - 9( x + 1/x) + 14 =
(x2-x)2+6(x2-x)+9
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708
(x2+2x2)2-6(x2+2x)+9
计算(x3+x2+x+2)/(x2+1)
十字相成法1.x2+2x-82.x2+5x+63.x2-8x+124.x2+x-205.2x2+9x+46.7x2-5x-27.8x2+2x-1
解方程:X2--1/8(X2+2X)+X2+2X/3(X2--1)=11
y=x+√(1-x2) y2=x2+(1-x2)+2x√(1-x2)
解方程 2/(x2-x)+6/(1-x2)=7/(x2+x)x2为的平方
x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x 化简
化简x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x
已知x2-4x+1=0,求x2/(x2)2-3x2+1
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708等会就要 再次坐等
因式分解 (x2-2x-x)(x2-2x+4)+9
1.2x2-3x+2>02.3x2+2x+1/3<03.16-24x小于等于-9x2
化简:根号(x2+6x+9)+根号(x2-2x+1)-根号(x2-4x+4)
计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2
化简x/x2+x除以x2+x-2/x2-1+x+1/x+2