比较1/log5(19)+2/log3(19)+3/log2(19) 和 1/log2(派)+2/log5(派)大小
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比较1/log5(19)+2/log3(19)+3/log2(19) 和 1/log2(派)+2/log5(派)大小
比较1/log5(19)+2/log3(19)+3/log2(19) 和 1/log2(派)+2/log5(派)大小
比较1/log5(19)+2/log3(19)+3/log2(19) 和 1/log2(派)+2/log5(派)大小
用换底公式
1/log5(19)=log5(5)/log5(19)=log19(5)
2/log3(19)=log3(9)/log3(19)=log19(9)
3/log2(19)=log19(8)
1/log5(19)+2/log3(19)+3/log2(19) =log19(22)
同理
1/log2(派)+2/log5(派)=logπ(29)
所以后面的式子更大
比较1/log5(19)+2/log3(19)+3/log2(19) 和 1/log2(派)+2/log5(派)大小
log5·log5(3)·log5(1/3)log3(5)·log5(3)·log5(1/3)log3(2)·log5(3)·log8(5)不好意思
log3^2/3与log5^6/5比较大小
log3^2/3与log5^6/5比较大小
log3^2/3与log5^6/5比较大小
比较下列各数的大小:2^0.7,log5(4),log1/3(5),log3(1/4),log4(1/3),
证明不等式1/log5(19)+2/log3(19)+3/log2(19)
证明不等式1/(log5(19))+(2/log3(19))+(3/log2(19))
8^(-1/3)+log3(1/27)+log6(5)*[log5(2)+log5(3)]+10^lg3=?
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
化简:log2 2+log5 1-3^(2log9 5)+(3log3 5)^2+3^log3 2
log3^2/3与log5^6/5比较大小 (希望详细点)
2log3^2-log3^(32/9)+log3^8-5log5^3=5log5^3改成5^log5^3
为什么1/log5(3)等于log3(5) ?
2007*log5(1)+log4(27)*log3(4)
2log3 2-log32/9+log3 8-5^log5 3
高一数学题(比较大小)log3(2),log5(2),log3(0.5),log0.6(0.1)本人比较笨,四个数一起比较的
若3/log2 19+2/log3 19+1/log5 19=log19 m,求m的值