求证1/sin2a+1/tan2a+1/sina=1/(tana/2)

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求证1/sin2a+1/tan2a+1/sina=1/(tana/2)
求证1/sin2a+1/tan2a+1/sina=1/(tana/2)

求证1/sin2a+1/tan2a+1/sina=1/(tana/2)
1/sin2a+1/tan2a+1/sina=1/sin2a+cos2a/sin2a+1/sina=(1+cos2a)/sin2a+1/sina
=(1+2cosa^2-1)/2sinacosa+1/sina
=cosa/sina+1/sina=(1+cosa)/sina
=(1+2cosa/2^2-1)/2(sina/2)(cosa/2)
=(cosa/2)/(sina/2)
=1/(tana/2)

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